Question

2.

How many kJ are required to change 10.0 grams of ice to water at 0°C?
general formula:

Answer 1

3.34 kJ

Step-by-step explanation:

m = Mass of ice = 10 g

L = Latent heat of ice = 334 J/g

Heat required to melt the ice at 0°C is given by

`Q=mL`

`\Rightarrow Q=10* 334`

`\Rightarrow Q=3340\ \text{J}`

`\Rightarrow Q=3.34* 10^3\ \text{J}`

`\Rightarrow Q=3.34\ \text{kJ}`

The heat required to melt the required amount of ice is 3.34 kJ