Question

1.

How many kJ are required to completely vaporize a 250 gram sample of water at 100°C?
general formula

Answer 1

565 kJ

Step-by-step explanation:

`H_v` = Heat of vaporization of water at 100°C = 2260 J/g

m = Mass of water = 250 g

Heat required is given by

`Q=mH_v`

`\Rightarrow Q=250* 2260`

`\Rightarrow Q=565000\ \text{J}`

`\Rightarrow Q=565* 10^3\ \text{J}`

`\Rightarrow Q=565\ \text{kJ}`

The heat required to vaporize the water is 565 kJ.