9514 1404 393
Answer:
see below for a table
Explanation:
You can easily identify intercept points by solving for one variable when the other is zero.
x-intercept (y=0)
4x = 12
x = 12/4 = 3
y-intercept (x=0)
-3y = 12
y = 12/-3 = -4
So, the coordinate pairs of these points are ...
(3, 0) and (0, -4)
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If you solve for y, you get ...
-3y = 12 -4x
y = (4/3)x -4 . . . . . divide by -3
This suggests that x being a multiple of 3 will be useful for finding integer values of y.
We already have points for x=0 and x=3. We can add points for x=6 and x=-3.
y = 4/3(6) -4 = 4
y = 4/3(-3) -4 = -8
So, the additional points are ...
(6, 4) and (-3, -8)