Question

Question 2 (2 points)

Saved
How many grams of water do will you need to prepare 480 g of 8.5% solution of
C6H12O6

Answer 1

`m_w=439.2g`

Step-by-step explanation:

Hello!

In this case, since the by-mass percent of a solution is a measure of the mass of the solute over the mass of the solution:

`\%m/m=(m_(solute))/(m_(solution)) *100\%`

As we know the mass of the solution and the by-mass percent, we can compute the mass of glucose in the 480 g of solution:

`m_(solute)=(\%m/m*m_(solution))/(100\%)`

Thus, by plugging in the data, we obtain:

`m_(solute)=(8.5\%*480g)/(100\%)=40.8g`

Finally, since the solution is made up of glucose and water, we compute the mass of water as follows:

`m_w=m_(sol)-m_(solute)=480g-40.8g\\\\m_w=439.2g`

Best regards!