Question

Based on the graph how many distinct real numbers solutions does the equation X^3 + 6x^2 + 12x + 8 = 0 have?

Answer 1

no real roots

Explanation:

Find discriminant of quadratic equation:

A

= 62 - 4aC

2 Identify a,b,c

Identify a,b,c through coefficient:

a

b

C

6

= 12

8

Substitute and calculate

Substitute the value of a,b,c and calculate

discriminant (b2 - 4ac) :

-48

Determine number of solution Determine number of solution with

discriminant:

no real roots