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If MgCl2 (aq) has a molarity of 2.5 M, then the molarity of the Cl-1 ions is ____ M.

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Answer:

molarity of Cl⁻ ions = 5.0 M

Step-by-step explanation:

The molarity of a solution expresses the amount in moles of a solution present in a litre of solvent. Its unit is mol/L or mol/dm³ written as M.

MgCl₂ when dissolved to form an aqueous solution dissociates into positive and negative ions, Mg²⁺and Cl⁻ ions.

Equation of the dissociation of MgCl₂ in aqueous solution is given below:

MgCl₂(aq) -----> Mg²⁺(aq) + 2Cl⁻(aq)

1 mole of aqueous MgCl₂ produces 2 moles of chloride ions, Cl⁻

Molar concentration of MgCl₂(aq) = 2.5 M

Molarity of chloride ions = number of moles of Cl⁻ ions * molarity of MgCl₂

molarity of Cl⁻ ions = 2 * 2.5 M

molarity of Cl⁻ ions = 5.0 M

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