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In an equation of the form k = ax^2 + bx + c with a > 0, the least possible value of k occurs at x = -b/(2a). In the equation k = (6x + 12)(x - 8), what is the least possible value for k?

User Rjalfa
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1 Answer

1 vote

Answer:


k= 6x^(2) -36x-96

Is what I got in a calculator but however, if you'd try and solve for K you won't get a complete answer.

Hope this helped :)

User SoCor
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