Answer:
{ - 2, 0, 2 }
Explanation:
To find the zeros let f(x) = 0 , that is
2x³ - 8x = 0 ← factor out 2x from each term
= 2x(x² - 4) = 0 ← (x² - 4) is a difference of squares
2x(x - 2)(x + 2) = 0
Equate each factor to zero and solve for x
2x = 0 ⇒ x = 0
x - 2 = 0 ⇒ x = 2
x + 2 = 0 ⇒ x = - 2
solution is { - 2, 0, 2 }