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42 votes
42 votes
NO LINKS!!! Please help me with this problem​

NO LINKS!!! Please help me with this problem​-example-1
User Chanafdo
by
2.8k points

2 Answers

12 votes
12 votes

Answer:

The sum of the probabilities of all possible outcomes is 1.

Given:

  • Male students = 25% = 0.25
  • Students who walk to school = 40% = 0.4

Therefore:

  • Female students = 1 - 0.25 = 0.75

Part (a)


\begin{aligned}\sf P(\textsf{female}) & = 1 - 0.25\\ & = 0.75\\ & = 75\%\end{aligned}

Part (b)


\begin{aligned}\sf P(\textsf{does not walk to school}) & = 1 - 0.4\\ & = 0.6\\ & = 60\%\end{aligned}


\begin{aligned}\implies\sf P(\textsf{student is male and does not walk to school}) & = 0.25 * 0.6\\ & = 0.15\\ & = 15\%\end{aligned}

Part (c)


\begin{aligned}\implies\sf P(\textsf{student walks to school or does not walk to school}) & = 0.4+0.6\\ & = 1\\ & = 100\%\end{aligned}

User SeikoTheWiz
by
2.9k points
13 votes
13 votes

Answer:

1. 0.75

2. 0.15

3. 1

Explanation:

1. P(student is female) = 1 - 0.25 = 0.75

2. P(student is male and does not walk to school) = 0.25 × 0.6 = 0.15

3. P(student walks to school or does not walk to school) = 0.4 + 0.6 = 1

User Exlord
by
3.3k points
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