Question

Solve the following 2 questions below, involving elements and reactions. *

1. There are 400 grams of NaCI in this substance. There are 10 drops in this substance. If each drop has an equal amount of NaCI in it, how much grams of NaCI are in 1 drop?

2. There are 800 grams of Barium peroxide in this mixture. There are 40 drops. If each drop has the same amount of Barium peroxide, how much is in 1 drop?

Please help me urgently with my homework, it would help much.

Answer 1

*Make proportions to solve. Find the rate from the question 1.

Question 1 is 40.

There are 400 grams of NaCI. There are 10 drops.

Divide 400 by 10.

400 / 10 = 40

40 is the answer.

Now all we do is repeat the same process for question 2.

Question 2 is 20.

There are 800 grams of barium peroxide, and there are 40 drops.

Divide 800 by 40.

800 / 40 = 20

Answer = 20.

Answer 2

1. 40 grams of NaCI

2. 20 grams of Barium Peroxide

Step-by-step explanation:

In this question, we have to divide to find the amount of each element in a drop.

For Question 1, there are 400 grams of NaCI. There are 10 drops.

So, we have to divide 400 by 10.

• 400 / 10 = 40

We get 40 as our result, so 40 is the answer.

Same for this question, we use the process we did before.

There are 800 grams of barium peroxide, and there are 40 drops.

So, we divide 800 by 40.

• 800 / 40 = 20

We have the answer as 20.

Our final answers are going to be listed below:

• Question 1 - 40
• Question 2 - 20

Hope this helps you!