Question

Which of the following points would be on the graph of the equation y=−4x+6?(−4, −10)(−4, 22)(1, −10)(1, −2)

Answer 1

Only the point (-4, 22) is ON THE GRAPH of the equation. Please also check the attached graph.

Explanation:

Given the equation

`y=-4x+6`

Let us substitute all the given points to check which points satisfy the equation.

Substitute (-4, -10) in the equation

`y=-4x+6`

`-10=-4(-4)+6`

`-10=16+6`

`-10=22`

As the R.H.S ≠ L.H.S, hence (-4, -10) does not satisfy the equation.

Hence, (-4, -10) is NOT ON THE GRAPH of the equation

Substitute (-4, 22) in the equation

`y=-4x+6`

`22 = -4(-4)+6`

`22 = 16+6`

`22 = 22`

As the R.H.S = L.H.S, hence (-4, 22) satisfies the equation.

Hence, (-4, 22) is ON THE GRAPH of the equation. Please also check the attached graph.

Substitute (1, -10) in the equation

`y=-4x+6`

`-10=-4(1)+6`

`-10=-4+6`

`-10=2`

As the R.H.S ≠ L.H.S, hence (1, -10) does not satisfy the equation.

Hence, (1, -10) is NOT ON THE GRAPH of the equation

Substitute (1, -2) in the equation

`y=-4x+6`

-2 = -4(1)+6

-2 = -4 + 6

-2 = 2

As the R.H.S ≠ L.H.S, hence (1, -2) does not satisfy the equation.

Hence, (1, -2) is NOT ON THE GRAPH of the equation

Therefore, from the above analysis, we conclude that only the point (-4, 22) is ON THE GRAPH of the equation. Please also check the attached graph.