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Arocket with an initial velocity of 20 m/s another engine that gives it an acceleration of 4 m/s ^ 2 over 10 secondsHow far did the rocket travel during this time

User Dsf
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1 Answer

3 votes

Answer:

50m

Step-by-step explanation:

Given parameters:

Initial velocity = 20m/s

Acceleration = 4m/s²

Time = 10s

Unknown:

Distance traveled by the rocket = ?

Solution:

To solve this problem use the expression below;

v² = u² + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

final velocity = 0

Insert the parameters and solve;

0² = 20² + 2 x 4 x s

-400 = 8s

s = 50m

Disregard the negative sign because distance cannot be negative.

User Manmohan Bohara
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4.1k points