Question

Graph the line that contains the point (-3,1) with a slope of 2/3

Answer 1

The graph of the line
`y=(2)/(3)x+3` that contains the point (-3,1) with a slope of 2/3 is attached below.

Explanation:

We know that the slop-intercept form of the equation is

`y=mx+b`

where m is the slope, and b is the y-intercept.

Given the slope = m = 2/3, and point (-3, 1)

`1=(2)/(3)\left(-3\right)+b`

`-(2)/(3)\cdot \:3+b=1`

`-2+b=1`

`b=3`

so the equation of line will be:

`y=mx+b`

`y=(2)/(3)x+3`

Also, the graph of the line
`y=(2)/(3)x+3` that contains the point (-3,1) with a slope of 2/3 is attached below.