Graph the line that contains the point (-3,1) with a slope of 2/3

Question

asked May 28, 2021 185k views

1 Answer

DrBloodmoney · Answer 1 · 2021-06-03T14:23:05+0000

Answer:

The graph of the line
y=(2)/(3)x+3 that contains the point (-3,1) with a slope of 2/3 is attached below.

Explanation:

We know that the slop-intercept form of the equation is

y=mx+b

where m is the slope, and b is the y-intercept.

Given the slope = m = 2/3, and point (-3, 1)

$1=(2)/(3)\left(-3\right)+b$

$-(2)/(3)\cdot \:3+b=1$

-2+b=1

b=3

so the equation of line will be:

y=mx+b

y=(2)/(3)x+3

Also, the graph of the line
y=(2)/(3)x+3 that contains the point (-3,1) with a slope of 2/3 is attached below.