Question

What is the equation of a line that is parallel to x−2y=−4 and passes through the point (0, 0)?

Enter your answer in the box.

Answer 1

The equation of a line that is parallel to x−2y=−4 and passes through the point (0, 0) will be:
`x-2y=0`

Explanation:

Given the line

`x-2y=-4`

`x+4 = 2y`

`y=\left((1)/(2)\right)x+2`

`m_1=(1)/(2)`

so, the slope of the line parallel to the given line would have

the same slope as
`(1)/(2)=m`, and passed through the point (0, 0).

Therefore, the equation of the required line is given by

`y = mx+b`

`y=\left((1)/(2)\right)x+0`

`y=\left((1)/(2)\right)x`

`2y=x`

`x-2y=0`

Therefore, the equation of a line that is parallel to x−2y=−4 and passes through the point (0, 0) will be:
`x-2y=0`