Complete question is;
In a hydraulic system, a 100-newton force is applied to a small piston with an area of 0.0020 m².
This hydraulic system should produce an output force of 50,000 newtons. How large an area should the output piston have?
Answer:
A2 = 1 m²
Explanation:
Using Pascal's Law which is here applied to mechanical advantage of a hydraulic piston, we can find the area of the large piston from;
F1/A1 = F2/A2
We are given;
Force of small piston: F1 = 100 N
Area of small piston; A1 = 0.0020 m²
Force of small piston: F2 = 50000 N
Thus;
Making A2 the subject, we have;
A2 = (F2/F1)A1
A2 = (50000/100) × 0.0020
A2 = 1 m²