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A three-phase Y-connected 50-Hz two-pole synchronous machine has a stator with 2000 turns of wire per phase. What rotor flux would be required to produce a terminal (line-to-line) voltage of 6 kV (rms value)?

User Natt
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1 Answer

4 votes

Answer:

The answer is "0.0045 Wb"

Step-by-step explanation:

Using formula:


\to E_A= √(2) \pi N_c f \phi\\\\\to \phi = (E_A)/(√(2) \pi N_c f)\\\\ .......(a)

Calculating the phase voltage of the machine:


V_\phi = (V_L)/(√(3))


= (4.16 * 10^3)/(√(3))\\\\=2401.7

Substitute the value from equation (a):


\phi= (2401)/(√(2) * \pi * 2000 * 60)


=4.503 * 10^(-3)\\\\= 0.0045 \ wb

The rotor flux = 0.0045 Wb

User Adam Burke
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5.6k points