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Tank has an average bearing pressure of 105 kPa. Ground water is deep. Calculate the total, pore and effective stress before tank loading and with tank

User Gypsa
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Answer:

Hello your question is incomplete attached below is the complete question

answer :

A) At 8 meters below center

Total stress = 228.827 KN/m^2

pore water pressure = 0 KN/m^2

effective stress = 228.827 - 0 = 228.827 KN/m^2

B) At 8 meters below tank edge

Total stress = 186.289 KN/m^2

pore water stress = 0 Kn/m^2

effective stress = 186.289 - 0 = 186.289 KN/m^2

Step-by-step explanation:

Given data :

Diameter = 21 m

radius = 21 / 2 = 10.5 m

soil moist = 18.4 KN/cubic meter

Average bearing pressure = 105 kPa

i) Before Loading Tank

Total stress = 8 * 18.4 = 147.2 KN/m^2

Pore pressure = 0 KN/m^2

Effective stress = 147.2 - 0 = 147.2 KN/m^2

ii) After loading Tank

No change occurs

A) At 8 meters below center

Total stress = 228.827 KN/m^2

pore water pressure = 0 KN/m^2

effective stress = 228.827 - 0 = 228.827 KN/m^2

B) At 8 meters below tank edge

Total stress = 186.289 KN/m^2

pore water stress = 0 Kn/m^2

effective stress = 186.289 - 0 = 186.289 KN/m^2

attached below is the detailed solution

Tank has an average bearing pressure of 105 kPa. Ground water is deep. Calculate the-example-1
Tank has an average bearing pressure of 105 kPa. Ground water is deep. Calculate the-example-2
User Michael Lehenbauer
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