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neon sign transformer has a 460W AC output with an rms voltage of 15 kV when connected to a normal household outlet. There are 500 turns of wire in the primary coil. How many turns of wire does the secondary coil have

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Answer:

The number of turns in the secondary coil is 62,500 turns.

Step-by-step explanation:

Given;

power of the transformer, P = 460 W

output voltage, V₂ = 15 kV = 15,000 V

input voltage of normal household outlet, V₁ = 120 V

number of turns in the primary coil, N₁ = 500 turns

number of turns in the secondary coil, N₂ = ?

Apply the following the transformer equation;


(N_2)/(N_1) = (V_2)/(V_1)\\\\N_2 = (V_2)/(V_1)*N_1\\\\N_2 = (15000)/(120)*500\\\\N_2 = 62500 \ turns

Therefore, the number of turns in the secondary coil is 62,500 turns.

User WaltPurvis
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