Answer:
The number of turns in the secondary coil is 62,500 turns.
Step-by-step explanation:
Given;
power of the transformer, P = 460 W
output voltage, V₂ = 15 kV = 15,000 V
input voltage of normal household outlet, V₁ = 120 V
number of turns in the primary coil, N₁ = 500 turns
number of turns in the secondary coil, N₂ = ?
Apply the following the transformer equation;

Therefore, the number of turns in the secondary coil is 62,500 turns.