Question

The distance (d) in miles that Cecil runs depends on the number of track practices (p) he attends. D = 2p + 3 i) Solvetheequation d=2p+3forp. ii) How many practices he has to attended to run 13 miles?

Answer 1

Answer: i)
`p=(d-3)/(2)`

ii) He has to attend 5 practices to run 13 miles.

Explanation:

Given: The distance (d) in miles that Cecil runs depends on the number of track practices (p) he attends.

`d=2p+3`

i) To solve for p . first subtract 3 from both sides , we get

`d-3=2p`

Divide both sides by 2

`(d-3)/(2)=p`

So.
`p=(d-3)/(2)`

ii) Put d= 13 , we get

`p=(13-3)/(2)=(10)/(2)=5`

i.e. he has to attend 5 practices to run 13 miles.