Question

According to Wikipedia the average volume of a human flatulence event is 185ML if the average body temperature is 98.6°F in the atmospheric pressure is 760.0 tour how many moles of gas does the average fart contain

Answer 1

0.00726mol

Step-by-step explanation:

Using general gas equation,

PV = nRT

Where;

P = pressure

V = volume

n = number of moles

R = gas constant (0.0821 L atm mol/K)

T = temperature

First, we need to convert the units of each variable

Volume = 185mL = 0.185L

Pressure = 760.0 torr = 1 atm

Temperature = 98.6°F = 310.15K

PV = nRT

1 × 0.185 = n × 0.0821 × 310.15

0.185 = 25.46n

n = 0.185/25.46

n = 0.00726mol