Answer:
4.7 x 10^14 Hz
Step-by-step explanation:
From Bohr's theory, the energy absorbed or emitted (ΔE) by an atom transiting from one energy level to another is given as;
ΔE = E4 - E2
Where;
E4 = energy corresponding to the energy level n=4
E2 = energy corresponding to the level n= 2
ΔE = (-2.10 x 10-19) - ( - 5.20 x 10-19)
ΔE =3.1 x 10-19
But
ΔE = hf
h = Plank's constant
f= frequency of photon absorbed
f = ΔE/h = 3.1 x 10-19/6.6 x 10-34
f = 4.7 x 10^14 Hz