Question

What is the distance, in meters, between adjacent fringes produced by a diffraction grating having 125 lines per centimeter

Answer 1

The correct answer will be "9×10⁻³ m".

Step-by-step explanation:

The given values are:

Number of lines

N = 125

As we know

The distance between the adjacent fringes is:

⇒
`(\lambda x)/(d)`

Where, λx = Screen distance

d = slit width

and,

⇒
`dSin \theta=m \lambda`

Where,
`d = (1)/(N)`

Hence,

⇒
`\Delta\gamma=(\lambda x)/(d)`

`=\lambda x* N`

On substituting the values, we get

⇒
`\Delta\gamma=575* 10^(-9)* 1.25* (125)/(10^(-2))`

⇒
`\Delta\gamma=9* 10^(-3) \ m`