Question

A household refrigerator consumes electrical energy at the rate of 200 W. lf electricity costs 5 k per kWh, calculate the cost of operating the appliance for 30 days

Answer 1

= 720000 [k]

Step-by-step explanation:

The cost is equal to 5 [$/kW-h], kilowatt per hour, this value should be multiplied by the power, and then by the time.

`5[(k)/(kw*h)]*200[w]*30[day]*24[(h)/(day) ]`

= 720000 [k]