Answer:
You can show that the function is one-to one by setting f(x)=f(y) and determining if f(x)=f(y)
Explanation:
So, you could
(y-2)^3+8=(x-2)^3+8 and determine if x=y
(y-2)^3=(x-2)^3
=cube root both sides
y-2=x-2
y=x
func is 1 to 1
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