Question

A shot-putter exerts a force of 140 N on a shotput, giving it an acceleration of 19 m/s2. What is the mass of the shot put?

Answer 1

The mass of the shotput is 7.37 Kg.

Step-by-step explanation:

Mechanical Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object. If the net force is zero, the object keeps moving at the same speed or keeps at rest (v=0).

A force of 140 N is exerted by a shot-putter on a shotput, which gets an acceleration of 19 m/s^2. We are required to calculate the mass of the shotput.

It can be done by solving the equation for m:

`\displaystyle m=(F)/(a)`

Substituting the given values:

`\displaystyle m=(140)/(19)`

m = 7.37 Kg

The mass of the shotput is 7.37 Kg.