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A line passes through the point (10,9) and has a slope of 3/2. Write an equation in slope intercept form for this line

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Answer:

The equation of line passing through (10,9) and having slope 3/2 is:
y = (3)/(2)x-6

Explanation:

The slope intercept form of a line is given by:


y=mx+b

We are given

Slope = m = 3/2

Point = (10,9)

Putting the value of the slope in the equation we get


y = (3)/(2)x+b

b is the y-intercept. To find the y-intercept we have to put the point through which the line passes in the equation.

Putting (10,9) in the equation


9 = (3)/(2)(10) +b\\9 = 15+b\\b = 9-15\\b = -6

Putting b=-6 in the equation


y = (3)/(2)x-6

Hence,

The equation of line passing through (10,9) and having slope 3/2 is:
y = (3)/(2)x-6

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