Answer:
The coordinates of P are (-2,0)
The radius of the circle is 5.
Explanation:
Analytic geometry
The diagram shows a circle with center P, and two points A(-6,3) and B(2,-3) that form the diameter of the circle.
a)
The center of the circle lies at the midpoint of A and B. The midpoint (xm,ym) can be calculated by:
![\displaystyle x_m=(x_1+x_2)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/yolp9tsacz0s9cntw2zx96eqdtj28dzwrp.png)
![\displaystyle y_m=(y_1+y_2)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/8rh3xmi90gwuagh579ub397mfnmeahz7va.png)
Substituting x1=-6, x2=2, y1=3, y2=-3:
![\displaystyle x_m=(-6+2)/(2)=(-4)/(2)=-2](https://img.qammunity.org/2021/formulas/mathematics/high-school/q29od2yvaj27hw61cihup8zbfs2mvj2lu8.png)
![\displaystyle y_m=(3-3)/(2)=0](https://img.qammunity.org/2021/formulas/mathematics/high-school/t27ph00g595t0f0ux5bn50ypgygcsstw25.png)
Thus, the coordinates of P are (-2,0)
b) The radius of the circle is the distance from the center to any point in its circumference. We can use the distance from P to A or B indistinctly.
Given two points A(x1,y1) and P(x2,y2), the distance between them is:
![d=√((x_2-x_1)^2+(y_2-y_1)^2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ykj4vnimechxgkuvrtfa2qltyc73jt9g88.png)
Substituting x1=-6, x2=-2, y1=3, y2=0:
![r=√((-2+6)^2+(0-3)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/d26lafn186gmrt1wq5tckclvsnfmfs101b.png)
![r=√(4^2+(-3)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/x7q2nqxr2b4lhglklyhbkcmscyxoxyxpar.png)
![r=√(16+9)=√(25)=5](https://img.qammunity.org/2021/formulas/mathematics/high-school/kw8j1yccrxrbsoxi5dd7xmsgmuesvoop2m.png)
The radius of the circle is 5.