Answer:
The minimum value of V(x) = 4
Explanation:
Step(i) :-
Given equation V(x) = x² - 6 x + 13 ...(i)
Differentiating equation (i) with respective to 'x' , we get
V¹ (x) = 2 x - 6 ...(ii)
2 x - 6 =0
2 x = 6
x = 3
Step(ii):-
Again Differentiating with respective to 'x' , we get
V¹¹(x) = 2 > 0
v(x)=x^2-6x+13
put x =3
The minimum value of V(x) = 9 - 18+13 = 4