![\huge\boxed{2\pi√(41)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/dhv9trkm26x5kuhr3mptsyyorwm9axlo3u.png)
Hey! Start by finding the radius. We will assume that point
is the center point of the circle, so the radius is the distance between points
and
.
Let's use the distance formula, substituting in the known values:
![\begin{aligned}r&=√((x_2-x_1)^2+(y_2-y_1)^2)\\&=√((-2-3)^2+(2-(-2))^2)\end{aligned}](https://img.qammunity.org/2021/formulas/mathematics/high-school/bkz3a6a108tbfm1a86xue6v36dn45syr87.png)
Simplify:
![\begin{aligned}r&=√((-2-3)^2+(2-(-2))^2)\\&=√((-5)^2+4^2)\\&=√(25+16)\\&=√(41)\end{aligned}](https://img.qammunity.org/2021/formulas/mathematics/high-school/lcsv3tzrziwjbzhsn4kmhlfhjojoojisun.png)
Now, we'll use the formula for the circumference of a circle, substituting in the known value:
![\begin{aligned}C&=2\pi r\\&=\boxed{2\pi√(41)}\\&\approx40.232\end{aligned}](https://img.qammunity.org/2021/formulas/mathematics/high-school/ppwcoaj6anqkjruheq5ivunpdn6d100kim.png)