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What is the equation of a line parallel to Y=-3x+5 that passes through point (6,8)?

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Answer:

y = -3x +26

Explanation:

We assume the given line is ...

y = -3x +5

This is in slope-intercept form:

y = mx +b

where m = -3 and b = 5.

The parameter m represents the slope of the line. A parallel line will have the same slope, so will be of the form ...

y = -3x +b

We can find the value of b using the given point:

8 = -3(6) +b

26 = b . . . . . . add 18

So, the equation of the parallel line through (6, 8) is ...

y = -3x +26

What is the equation of a line parallel to Y=-3x+5 that passes through point (6,8)?-example-1
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