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What is the mean absolute deviation of Sherwin's homework scores? HELP

What is the mean absolute deviation of Sherwin's homework scores? HELP-example-1
What is the mean absolute deviation of Sherwin's homework scores? HELP-example-1
What is the mean absolute deviation of Sherwin's homework scores? HELP-example-2

2 Answers

7 votes

Answer:

6

Step-by-step explanation:

The mean is the values divided by how many values there are.

20 + 13 + 3 = 36 36 / 3 = 12

The mean deviation is the absolute value of the difference between the mean and the values.

|20 - 12| = 8

|13 - 12| = 1

|3 - 12| = 9

The mean absolute deviation is the mean of those values.

8 + 1 + 9 = 18

18 / 3 = 6

User James McMahon
by
5.2k points
3 votes

Answer: 6

======================================================

Step-by-step explanation:

First we need to find the mean.

Add up the values to get 20+13+3 = 33+3 = 36

Then divide that sum by 3 because we're dealing with three values

We get 36/3 = 12.

The mean is 12.

--------------------------

From here we subtract the mean (12) from each data value of the set {20,13,3}

So we get these differences

  • 20-12 = 8
  • 13-12 = 1
  • 3-12 = -9

Here's where the term "absolute" comes in. More specifically, we'll use absolute value. This is to ensure we don't get a negative value when we subtract. So whatever results above are negative, we just flip to the positive version when we apply absolute value.

  • |20-12| = 8
  • |13-12| = 1
  • |3-12| = 9 .... this value is now positive

--------------------------

The set of results we got were {8, 1, 9}

Let's compute the mean of this new set

Add up the values: 8+1+9 = 9+9 = 18

Divide by three: 18/3 = 6

The mean absolute deviation is 6.

User SeanCAtkinson
by
5.0k points
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