Question

What is the point slope equation of the line through (3,6) (5,-8)

Answer 1

y-6 = -7(x-3)

Explanation:

`y-y_(1) =m(x-x_(1))`

y - 6 = m(x - 3)

`m = (-8-6)/(5-3)=(-14)/(2)=-7`

y-6 = -7(x-3)

Answer 2

y - 6 = -7(x - 3)

General Formulas and Concepts:

Pre-Algebra

• Order of Operations: BPEMDAS

Algebra I

Slope Formula:
`m=(y_2-y_1)/(x_2-x_1)`

Point-Slope Form: y - y₁ = m(x - x₁)

• x₁ - x coordinate

• y₁ - y coordinate

• m - slope

Explanation:

Step 1: Define

Point (3, 6)

Point (5, -8)

Step 2: Find slope m

1. Substitute:
   `m=(-8-6)/(5-3)`
2. Subtract:
   `m=(-14)/(2)`
3. Divide:
   `m=-7`

Step 3: Write equation

Point (3, 6)

Slope m = -7

y - 6 = -7(x - 3)