Question

How many grams are in 4.5 x 10^22 molecules of Ba(NO2)2

Answer 1

17 g Ba(NO₂)₂

General Formulas and Concepts:

Chemistry

• Stoichiometry
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Step-by-step explanation:

Step 1: Define

4.5 × 10²² molecules Ba(NO₂)₂

Step 2: Define conversion

Molar Mass of Ba - 137.33 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(NO₂)₂ - 137.33 + 2(14.01) + 4(16.00) = 229.35 g/mol

Step 3: Dimensional Analysis

`4.5 \cdot 10^(22) \ mc \ Ba(NO_2)_2((1 \ mol \ Ba(NO_2)_2)/(6.022 \cdot 10^(23) \ mc \ Ba(NO_2)_2) )((229.35 \ g \ Ba(NO_2)_2)/(1 \ mol \ Ba(NO_2)_2) )`

= 17.1384 g Ba(NO₂)₂

Step 4: Check

We are given 2 sig figs. Follow sig fig rules.

17.1384 g Ba(NO₂)₂ ≈ 17 g Ba(NO₂)₂