What is the OH- in a solution that has a H+ = 2×10-5 M

asked Oct 16, 2021 44.9k views

1 vote

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4 votes

Answer:

Step-by-step explanation:

{H+}*[OH-] = 1 * 10^-14

[2*10^-5]* [OH^-] = 1*10^-14

[OH^-] = 1*10^-14/2*10^-5

[OH^-] = 5*10^-10

Eaolson answered Oct 20, 2021

6.0k points

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