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If f(x) = (2x^3 − 4)^6, then what is f '(x)? 21x^2(x^3 − 4)^5 21x^8 6(2x^3 − 4)^5 6(2x^3 − 4)^5(6x^2)
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If f(x) = (2x^3 − 4)^6, then what is f '(x)?

21x^2(x^3 − 4)^5
21x^8
6(2x^3 − 4)^5
6(2x^3 − 4)^5(6x^2)

User Jim In Texas
by
7.9k points

1 Answer

3 votes
The correct answer is:

6(2x^3-4)^5(6x^2)

Step-by-step explanation:

That is the derivative after you differentiate using the Chain Rule.
User Sandrin Joy
by
8.6k points
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