Question

(2 points) How many grams of K2SO4 are present in 25.0 mL of 7.00 % (m/v) solution?

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Answer 1

Mass of K₂SO₄ : 1.75 g

Further explanation

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

volume of solution = 25 ml

% (m/v)=7%

mass of K₂SO₄ :

`\tt \%m/v=(mass~of~solute)/(volume~of~solution)* 100\%\\\\7\%=(mass~K_SO_4)/(25)* 100\%\\\\mass~K_2SO_4=7* 25/ 100=1.75~g`