56.5k views
3 votes
How many moles are in 428 L of chlorine gas

User Skybunk
by
5.8k points

1 Answer

3 votes

Answer:

19.3 moles

Step-by-step explanation:

In order to calculate the number of moles of Chlorine gas from the volume, we have to calculate its mass from its known density using the formula:

Density (g/L) = mass (g) /volume (L)

Density of Chlorine gas= 3.2g/L

Volume = 428L

3.2 = mass/428

mass = 428 × 3.2

mass = 1369.6g

Using mole = mass ÷ molar mass

Molar mass of chlorine (Cl2) = 35.5 × 2

= 71g/mol

mole = 1369.6 ÷ 71

mole = 19.2901

mole = 19.3 moles

User N D Thokare
by
4.9k points