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If 6982.6 J of energy is used, how many grams of ice can be melted?

1 Answer

2 votes

20.91 grams of ice can be melted

Further explanation

Q fusion = m x L

L = latent heat , kj/kg

m = mass, kg

Q = heat, kJ

Reaction :

H₂O(s)⇒H₂O(l)

Q = 6982.6 J=6.9826 kJ

L for ice = 3.34 x 10⁵ J/kg=334 kJ/kg

mass of ice :


\tt m=(Q)/(L)\\\\m=(6.9826)/(334)=0.020905~kg= 20.91~g

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