Question

Can y’all please help

Answer 1

The cat's speed when it slid off the table was 2.53 m/s

Step-by-step explanation:

Horizontal Motion

When an object is thrown horizontally at a speed v, from a height h, it describes a curved path ruled by gravity, until it hits the ground.

the range or maximum horizontal distance traveled by the object can be calculated as follows:

`\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}`

The situation described in the problem fits into the concept of a horizontal launch when the cat slides off the table and gets to the ground some distance ahead.

It's given the range as d=1.3m and the height h=1.3 m, thus we can find the cat's speed by solving the equation for v:

`\displaystyle v=d\cdot\sqrt{\frac {g}{2h}}`

Where
`g=9.81\ m/s^2`

Substituting values:

`\displaystyle v=1.3\cdot\sqrt{\frac {9.81}{2\cdot 1.3}}`

`\displaystyle v=1.3\cdot\sqrt{\frac {9.81}{2.6}}`

Calculating:

v = 2.53 m/s

The cat's speed when it slid off the table was 2.53 m/s