1 Answer

Zelid · Answer 1 · 2021-03-21T00:55:06+0000

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Let t as y² + 5y .

${y}^(2) + 5y = t$

Rewrite the equation :

$t - (36)/(t) = 0 \\$

Multiply sides by t

$t * (t - (36)/(t) ) = t * 0 \\$

${t}^(2) - 36 = 0$

Add sides 36

${t}^(2) - 36 + 36 = 0 + 36$

${t}^(2) = 36$

$t = ± \: 6$

_________________________________

So :

${y}^(2) + 5y = 6$

Subtract sides 6

${y}^(2) + 5y - 6 = 6 - 6$

${y}^(2) + 5y - 6 = 0$

(y + 6)(y - 1) = 0

$y = - 6 \: \: or \: \: y = 1$

##############################

${y}^(2) +5y = - 6$

$No \: \: solution$

_________________________________

Thus (( y = 1 )) and (( y = - 6 )) are the roots of the equation .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Please log in or register to add a comment.