Question

You roll a unbalanced die 500 times, and a 3-spot is obtained 110 times. The probability of obtaining the 3-spot for this die is approximately?

Answer 1

Answer:
`(11)/(50)`

Explanation:

Formula: Probability =
`\frac{\text{Favorable outcomes}}{\text{Total outcomes}}`

Given: Total number of times unbalanced die thrown = 500 (Total outcomes)

Number of times 3-spot is obtained = 110 (Favourable outcomes)

The probability of obtaining the 3-spot for this die
`=(110)/(500)`

`=(11)/(50)=0.22`

The probability of obtaining the 3-spot for this die is 0.22 .