Question

A slingshot to launch 0.210kg rock straight up in the air. The sling shot excerts an average force of 55N on the rock. Assume friction is negligible. What is the ney force on the rock while in the process of being shot?

Answer 1

F = 52.93 [N]

Step-by-step explanation:

Since the Rock is thrown upwards, there are only two forces, one is the force of the rubber (55[N]) and the other is the force of gravitational acceleration acting in the opposite direction to the movement of the rock, therefore this acceleration will be taken as negative.

F = 55 - m*g

where:

F = total force [N] (units of Newtons)

m = mass = 0.21 [kg]

g = gravity acceleration = 9.81 [m/s²]

F = 55 - (0.21*9.81)

F = 52.93 [N]