Answer:
n(n-1) is even for all integers.
Explanation:
We have:
And we would like to determine its parity.
Case 1: n is Even:
If n is even, then we will have an even number (n) multiplied by an odd number (n-1).
Since anything multiplied by an even number is even, n(n-1) is even for all even values.
Care 2: n is Odd:
If n is odd, then we will still have an odd number (n) multiplied by an even number (n-1).
And again, this will yield an even number.
Therefore, n(n-1) will be even for all integers.