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What is the discriminant of the quadratic equation, 4x^2-8x-5=0​

User Quaspas
by
7.2k points

2 Answers

4 votes

Answer:

Explanation:

4x^2-8x-5=0

The discriminant is the number under the √. In this case it's 144

User George Pavelka
by
6.9k points
5 votes

Answer:


\Delta=144

Explanation:

For a quadratic in standard form, the discriminant is given by:


\Delta=b^2-4ac

We have the equation:


4x^2-8x-5=0

Hence, our a=4; b=-8; and c=-5.

Substituting into our formula, we acquire:


\Delta=(-8)^2-4(4)(-5)

Evaluate:


\Delta=64+80

Add:


\Delta=144

Therefore, our discriminant is 144.

Notes:

Since our discriminant is a positive value, this tells us that our quadratic has two real roots.

User Malhobayyeb
by
6.6k points
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