Question

Find the center and radius of the circle with the equation: (x-5)^2+(y+1)^2=4

Answer 1

Centre (5,-1) radius =2

Explanation:

(x-5)^2+(y+1)^2=4

The standard equation of the circle is

(X-a)^2+(y-b)^2=r^2

Where a,b is centre of the circle and r is the radius of the circle

Compare the equations

So we get a=5,b=-1 and r=2

Centre (5,-1) radius =2