Question

How long does it take for an 8 kg pumpkin to hit the ground if dropped from a height of 55 m.

Answer 1

t = 3.35 s

Step-by-step explanation:

It is given that,

Mass of a pumpkin, m = 8 kg

It is dropped from a height of 55 m

We need to find the time taken by it to hit the ground.

Initial velocity of the pumpkin, u = 0

Using second equation of motion to find it as follows :

`h=ut+(1)/(2)at^2\\\\t=\sqrt{(2h)/(g)} \\\\t=\sqrt{(2(55))/(9.8)} \\\\t=3.35\ s`

So, it will take 3.35 seconds to hit the ground.