Question

1.33 kg of ice at 0.00 °C is added to 12.4 kg of water at 20.0 °C. What is the final temperature?

Answer 1

Heat gain = Heat loss

Latent heat of fusion of water = 80 kcal/kg

Specific heat of water = 1 kcal /kg deg C

Heat gain = 1.33 * 80 + (12.4 + 1.33) T = 106 + 13.7 T

Heat Loss = 12.4 * (20 - T) = 248 - 12.4 ΔT

106 + 13.7 T = 248 - 12.4 T

26.1 T = 142

T = 5.4 final temperature

Answer 2

Answer: 10.310406 (works for acellus)

I tried to add an explanation but it wouldn't let me for some reason

Anyways watch the end of the video to see how to get the equation