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What is the final temperature when 625 grams of water at 75.0° C loses 7.96 x 104 J? The specific heat of water is 4.18 J/gCº.
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What is the final temperature when 625 grams of water at 75.0° C loses 7.96 x 104 J?

The specific heat of water is 4.18 J/gCº.

User Rahn
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Answer: A copper cylinder has a mass of 76.8 g and a specific heat of 0.092 cal/g·C. It ... J ql = mwcwΔTw. ΔTw = ql/(m x c). ΔTw = 7.96 x 10. 4. J/(625 g x 4.18 J/g·K) = 30.5 ...

Step-by-step explanation:

User Keego
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