Question

Help me pleaseeee!!!​

Answer 1

Explanation:

the answer is (D)
`\sqrt[4]{3x^2}` / 2y

Answer 2

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Answer:

`\frac{\sqrt[4]{3x^2}}{2y}`

Explanation:

Fourth powers (and multiples of 4th powers) can be factored out from under the radical. Everything else remains under the radical.

`\sqrt[4]{(24x^6y)/(128x^4y^5)}=\left((3\cdot8)/(16\cdot8)x^(6-4)y^(1-5)\right)^(1/4)=(3\cdot2^(-4)x^(2)y^(-4))^(1/4)\\\\=\boxed{\frac{\sqrt[4]{3x^2}}{2y}}`

_____

The applicable rules of exponents are ...

a^(b/c) = c-th root of (a^b)

(a^b)(a^c) = a^(b+c)

(a^b)^c = a^(bc)

a^-b = 1/a^b