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Is the following relation a function? Yes or no

Is the following relation a function? Yes or no-example-1
User Rizzy
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2 Answers

3 votes

Answer:

It is a many-to-many function but not a one-to-ine function hence, it cannot be represented a a function in an expression

Explanation:

Topic: Functions

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User Ryan Kennedy
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1 vote

Answer: No

Explanation: I think that the least confusing way to do

this problem is to first write down the ordered pairs that

are represented by this mapping diagram.

So we have {(6,3), (-1, 2), (-1, -1), (4, 3)}.

In order for a relation to be a function, each x-coordinate needs

to appear once unless we have a repeated ordered pair.

Since we have the same x-coordinate in two of

our ordered pairs, this relation cannot be a function.

In terms of the mapping diagram, you can see that we have

an x that is paired with two different y's.

So this does not fit the definition of a function which states

that each x must be paired with exactly one y.

User Pavik
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